A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant?
Accepted Solution
A:
Answer:776.46 mStep-by-step explanation:According to the scenario it is a question of right angle triangleTo find the height of the plane above the ground we will use trigonometry identity.sinФ = opposite / hypotenuse here Ф = 15° opposite = height hypotenuse = 3000m Plug values in the formula above sin(15) = height / 3000height = sin(15)(3000) = 776 .46 m(make sure your calculator is in degree mode)