Which of the following represents 3x-5y+10=0 written in slope-intercept form?

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:[tex]y = mx + b[/tex]Where:m: Is the slopeb: Is the cut-off point with the y axisWe have the following equation:[tex]3x-5y + 10 = 0[/tex]We manipulate algebraically:We subtract 10 from both sides of the equation:[tex]3x-5y = -10[/tex]We subtract 3x from both sides of the equation:[tex]-5y = -3x-10[/tex]We multiply by -1 on both sides of the equation:[tex]5y = 3x + 10[/tex]We divide between 5 on both sides of the equation:[tex]y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2[/tex]Thus, the equation in the slope-intercept form is [tex]y = \frac {3} {5} x + 2[/tex]Answer:[tex]y = \frac {3} {5} x + 2[/tex]