Q:

The manager of a school bookstore has found four different companies from which she may order book bags. The algebraic r ules shown for each company represent the cost of placing a book bag order, c, based on the number of book bags purchased, bCompany A: c = 12bCompany B: c = 8.25b + 55Company C: 8b + 100Company D: c = 15b - 55Write a situation for each algebraic rule, if possible.Company A:Company B:Company C:Company D:

Accepted Solution

A:
YOU'D BETTER MARK FRENCH BRAINLIEST! LOLAnswer:We are going to set a few rules for this one:c = the cost of placing a book bag order. (Variable already set).b = the number of book bags purchased, and the set number of book bags purchased will be 50. (Just an example).Now that that's set, Let's solve!Company A:c = 12b              [substitue in values]c = 12(50)          [solve]c = 600So the cost of the book bags for Company A is $600.Company B:c = 8.25b + 55           [substitute in values]c = 8.25(50) + 55       [solve]c = 412 + 55               [solve]c = 467.50So the cost of the book bags for Company B is $467.50.Company C:c = 8b + 100               [substitute in values]c =   8(50) + 100         [solve]c = 400 + 100             [solve]c = 500So the cost of the book bags for Company C is $500.Company D:c = 15b - 55              [substitute in values]c = 15(50) - 55          [solve]c = 750 - 55              [solve]c = 695So the cost of the book bags for Company D is $695.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~The least expensive company was Company B, and the most expensive company was Company D. (Not that you were asking).I hope this helps!- redone by moi